Bourbaki

Proposition 7

Tag 0E06, permanent. Cite it as [Bourbaki, Tag 0E06].

Algebra, chapter X, § 7. Produit de composition

a) Let

(ε)

0→P′→fP→gP′′→0 0 \to P' \xrightarrow{f} P \xrightarrow{g} P'' \to 0
be an exact sequence of right AA-modules, θ∈ExtA1(P′′,P′)\theta \in \mathrm{Ext}_A^1(P'', P') the associated class, MM a left AA-module. The connecting homomorphism
δn(E,M):TornA(P′′,M)→Torn−1A(P′,M) is the mapping γ↦θ∘γ. \delta_n(\mathscr{E}, M) : \mathrm{Tor}_n^A(P'', M) \to \mathrm{Tor}_{n-1}^A(P', M) \text{ is the mapping } \gamma \mapsto \theta \circ \gamma .

b) Let

(ε₁)

0→M′→M→M′′→0 0 \to M' \to M \to M'' \to 0
be an exact sequence of left AA-modules, θ1∈ExtA1(M′′,M′)\theta_1 \in \mathrm{Ext}_A^1(M'', M') the associated class, PP a right AA-module. The connecting homomorphism
δn(P,E1):TornA(P,M′′)→Torn−1A(P,M′) is the mapping γ↦θ1∘γ. \delta_n(P, \mathscr{E}_1) : \mathrm{Tor}_n^A(P, M'') \to \mathrm{Tor}_{n-1}^A(P, M') \text{ is the mapping } \gamma \mapsto \theta_1 \circ \gamma .
Let γ∈TornA(P′′,M)\gamma \in \mathrm{Tor}_n^A(P'', M) be the class of a cycle z′′∈Z˙n(L(P′′)⊗AL(M))z'' \in \dot{Z}_n(L(P'') \otimes_A L(M)), and let
0⟶P′→fP→gP′′⟶0↑u1↑u0↑1L1(P′′)→d1L0(P′′)→p0′′P′′⟶0 \begin{array}{ccccccccc} 0 & \longrightarrow & P' & \xrightarrow{f} & P & \xrightarrow{g} & P'' & \longrightarrow & 0 \\ & & \uparrow u_1 & & \uparrow u_0 & & \uparrow 1 & & \\ L_1(P'') & \xrightarrow{d_1} & L_0(P'') & \xrightarrow{p_0''} & P'' & \longrightarrow & 0 \end{array}
be a commutative diagram. We shall denote by p′:L(P′)→P′p' : L(P') \to P' and p′′:L(P′′)→P′′p'' : L(P'') \to P'' the canonical morphisms of complexes. By definition, δ(γ)∈Torn−1A(P′,M)\delta(\gamma) \in \mathrm{Tor}_{n-1}^A(P', M) is obtained as follows: one chooses x∈P⊗Ln(M)x \in P \otimes L_n(M) such that (g⊗1)(x)=(p′′⊗1)(z′′)(g \otimes 1)(x) = (p'' \otimes 1)(z'') and δ(γ)\delta(\gamma) is the class of cycles z′∈Zn−1(L(P′)⊗L(M))z' \in Z_{n-1}(L(P') \otimes L(M)) such that
(f⊗1)(p′⊗1)(z′)=(1⊗dn)(x). (f \otimes 1)(p' \otimes 1)(z') = (1 \otimes d_n)(x) .
For 0≤i≤n0 \leq i \leq n, let zi′′z''_i be the component of z′′z'' in Li(P′′)⊗Ln−i(M)L_i(P'') \otimes L_{n-i}(M); we have
0=Dz′′=∑i(di⊗1+(−1)i⊗dn−i)(zi′′), 0 = Dz'' = \sum_i (d_i \otimes 1 + (-1)^i \otimes d_{n-i})(z''_i) ,
hence (di⊗1)(zi′′)=(−1)i⊗dn−i+1(zi−1′′)(d_i \otimes 1)(z''_i) = (-1)^i \otimes d_{n-i+1}(z''_{i-1}) and in particular
(d1⊗1)(z1′′)=−1⊗dn(z0′′). (d_1 \otimes 1)(z''_1) = -1 \otimes d_n(z''_0) .
Let us then choose x=(u0⊗1)(z0′′)x = (u_0 \otimes 1)(z''_0): we indeed have
(g⊗1)(x)=(p0′′⊗1)(z0′′)=(p′′⊗1)(z′′). (g \otimes 1)(x) = (p_0'' \otimes 1)(z''_0) = (p'' \otimes 1)(z'') .
Since
(1⊗dn)(x)=(u0⊗1)(1⊗dn)(z0′′)=−(u0⊗1)(d1⊗1)(z1′′)=−(f⊗1)(u1⊗1)(z1′′), (1 \otimes d_n)(x) = (u_0 \otimes 1)(1 \otimes d_n)(z''_0) = - (u_0 \otimes 1)(d_1 \otimes 1)(z''_1) = - (f \otimes 1)(u_1 \otimes 1)(z''_1) ,

it follows that δ(γ)\delta(\gamma) is the class of cycles z′∈Zn−1(L(P′)⊗AL(M))z' \in Z_{n-1}(L(P') \otimes_A L(M)) such that (p′⊗1)(z′)=−(u1⊗1)(z1′′)(p' \otimes 1)(z') = - (u_1 \otimes 1)(z''_1). But, by definition, the class θ\theta corresponds via the isomorphism ExtA1(P′′,P′)→H1(HomgrA(L(P′′),P′))\mathrm{Ext}_A^1(P'', P') \to H^1(\mathrm{Homgr}_A(L(P''), P')) to the class of the morphism f:L(P′′)(1)→P′f : L(P'')(1) \to P' defined by −u1- u_1, and the product θ∘γ\theta \circ \gamma is the class of cycles

z‾′∈Zn−1(L(P′)⊗AL(M))such that(p⊗1)(z‾′)=f(z′′)=−(u1⊗1)(z1′′), \overline{z}' \in Z_{n-1}(L(P') \otimes_A L(M)) \quad \text{such that} \quad (p \otimes 1)(\overline{z}') = f(z'') = - (u_1 \otimes 1)(z''_1),
which completes the proof of a). Assertion b) follows from a) by the commutation isomorphisms.

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

Cited by

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Cites

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Translated with machine help, not yet reviewed by a person.