Bourbaki

Theorem 1

Tag 0E37, permanent. Cite it as [Bourbaki, Tag 0E37].

Algebra, chapter X, § 9. Complexes de Koszul

Consider the following conditions: (i) The sequence xx is M-regular (X, p. 158). (ii) The sequence xx is completely secant for M (X, p. 157, def. 2). (iii) One has H1(x,M)=0H_1(x, M) = 0. (iv) The homomorphism αMx:(A[X1,...,Xn]/d)⊗AM→⨁r≥0xrM\alpha_M^x : (A[X_1, ..., X_n]/\mathfrak{d}) \otimes_A M \to \bigoplus_{r \geq 0} x^r M is bijective. (v) The homomorphism βMx:(A/x)[X1,...,Xn]⊗AM→⨁r≥0(xrM/xr+1M)\beta_M^x : (A/x)[X_1, ..., X_n] \otimes_A M \to \bigoplus_{r \geq 0} (x^r M/x^{r+1} M) is bijective.

Then one has the implications (i) ⇒\Rightarrow (ii) ⇒\Rightarrow (iii) ⇔\Leftrightarrow (iv) ⇒\Rightarrow (v). If for 1≤i≤n1 \leq i \leq n the A-module M/(x1M+⋯+xi−1M)M/(x_1 M + \cdots + x_{i-1} M) is separated for the xx-adic topology, the conditions (i) to (v) are equivalent.

The theorem will be proved in Nos 8 and 9.

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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Cites

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