Bourbaki

习题 14, § 5

标签 07WD,永久不变。引用为 [Bourbaki, Tag 07WD]。

拓扑向量空间, IV, p. 69

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令 EE 为 Banach 空间满足可数性第一公理。 如果满足以下性质,EE的元素的序列(en)n≥0(e_n)_{n \geq 0}被称为*Banach基*:对于每个x∈Ex \in E,存在一个唯一的标量序列(an)(a_n),使得x=∑n=0∞anenx = \sum_{n=0}^\infty a_n e_n,其中右侧的级数是收敛的。 a) 表明家庭(en)(e_n)是完整且自由的。 令EnE_n为由eme_m为指标m≤nm \leq n生成的EE的向量子空间(闭合),并令PnP_n为从EE到由Pn⋅(∑m=0∞amem)=∑m=0namemP_n \cdot (\sum_{m=0}^\infty a_m e_m) = \sum_{m=0}^n a_m e_m定义的EnE_n的投影算子。 Show that the PnP_n are continuous linear mappings and that sup⁡n∥Pn∥<+∞\sup_n \|P_n\| < +\infty. (Consider the norm on EE defined by ∥∑n=0∞anen∥=sup⁡n∥∑m=0namem∥\left\| \sum_{n=0}^\infty a_n e_n \right\| = \sup_n \left\| \sum_{m=0}^n a_m e_m \right\|; show that EE is complete for this norm and deduce that it is equivalent to the given norm on EE (cf. I, p. 17, th. 1).) Show that for every pair of integers p<qp < q, the norm of the projection Pq,pP_{q,p} of EqE_q onto EpE_p, which is parallel to the vector subspace generated by the eme_m for indices mm such that p+1≤m≤qp + 1 \leq m \leq q, is bounded by a number independent of p,qp, q. b) Conversely, let (en)(e_n) be a total sequence of elements of EE, which is a free family and is such that the norms of the projections Pq,pP_{q,p} for 0≤p<q0 \leq p < q are bounded by a number MM independent of pp and qq. 证明 (en)(e_n) 是 EE 的 Banach 基。 (首先证明序列(en)(e_n)是拓扑自由的并且定义投影算子PnP_n;然后∥Pn∥≤M\|P_n\| \leq M对于所有nn。 接下来观察,如果d(x,En)d(x, E_n)是点x∈Ex \in E到EnE_n的距离,则∥x−Pn⋅x∥≤(M+1) d(x,En)\|x - P_n \cdot x\| \leq (M + 1)\ d(x, E_n)。)[^1]

[^1]: It is clear that the existence of a Banach basis in EE implies that EE satisfies the first axiom of countability. 但是 Banach 空间满足的例可数性第一公理,其中不存在 Banach 基 (P. Enflo, Acta Math., t. CXXX(1973),p. 309-317)。

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