Bourbaki

Exercise 10, § 5

Commutative Algebra, II

So let A be a ring, E(A)E(A) the set of classes of finitely generated projective A-modules; let G be the Z\mathbf{Z}-module of formal linear combinations of the elements of E(A)E(A), N the submodule of G formed by the elements ξ−ξ′−ξ′′\xi - \xi' - \xi'', where ξ,ξ′,ξ′′\xi, \xi', \xi'' are the classes of three finitely generated projective A-modules M, M', M'' such that there exists an exact sequence

0→M′→M→M′′→0 0 \to M' \to M \to M'' \to 0

(it amounts to the same thing to say that M is isomorphic to the direct sum M′⊕M′′M' \oplus M'' by virtue of Alg., chap. II, 3rd ed., § 2, no 2). Let K(A)K(A) be the Z\mathbf{Z}-module quotient G/N, and for every finitely generated projective A-module M, let χ(M)\chi(M) (or χA(M)\chi_A(M)) be its class in K(A)K(A).

a) Now prove that there exists on K(A)K(A) one and only one structure of a commutative ring whose addition is that of the Z\mathbf{Z}-module K(A)K(A) and whose multiplication is such that χ(M)χ(N)=χ(M⊗AN)\chi(M)\chi(N) = \chi(M \otimes_A N) for two finitely generated projective A-modules, M, N; χ(A)\chi(A) is the unit element of K(A)K(A).

b) For every finitely generated projective A-module M and every integer p⩾0p \geqslant 0 denote by λp(M)\lambda^p(M) the element χ(⋀pM)\chi(\bigwedge^p M) of K(A)K(A). Now prove that one has λp(M⊕N)=∑r+s=pλr(M).λs(N)\lambda^p(M \oplus N) = \sum_{r+s=p} \lambda^r(M).\lambda^s(N). Denote by λT(M)\lambda_T(M) the element ∑p=0∞λp(M)Tp\sum_{p=0}^\infty \lambda^p(M)T^p in the ring K(A)[[T]]K(A)[[T]] of formal series in one indeterminate over the ring K(A)K(A); now prove that λT(M⊕N)=λT(M)λT(N)\lambda_T(M \oplus N) = \lambda_T(M)\lambda_T(N); deduce a homomorphism again denoted x→λT(x)x \to \lambda_T(x) from K(A)K(A) into the multiplicative group of formal series of K(A)[[T]]K(A)[[T]] whose constant term is equal to 1. The coefficient of TpT^p in λT(x)\lambda_T(x) will be denoted by λp(x)\lambda^p(x); one has

λp(x+y)=∑r+s=pλr(x)λs(y) \lambda^p(x+y) = \sum_{r+s=p} \lambda^r(x)\lambda^s(y)

for x,yx, y in K(A)K(A).

c) If A is a local ring, the ring K(A)K(A) identifies canonically with Z\mathbf{Z}, and one has λp(n)=(np)\lambda^p(n) = \binom{n}{p}. Deduce that, if A is a direct composition of m local rings, K(A)K(A) is isomorphic to Zm\mathbf{Z}^m.

d) Let φ:A→B\varphi : A \to B be a homomorphism of rings. Now prove that there exists one and only one homomorphism of rings φ!:K(A)→K(B)\varphi^! : K(A) \to K(B) such that φ!(χA(M))=χB(M(B))\varphi^!(\chi_A(M)) = \chi_B(M_{(B)}) for every finitely generated projective A-module M; one has φ!(λp(x))=λp(φ!(x))\varphi^!(\lambda^p(x)) = \lambda^p(\varphi^!(x)) for every x∈K(A)x \in K(A); if ψ:B→C\psi : B \to C is a second homomorphism of rings, one has (ψ∘φ)!=ψ!∘φ!(\psi \circ \varphi)^! = \psi^! \circ \varphi^!.

e) Let φ:A→B\varphi : A \to B be a homomorphism of rings, for which B is a finitely generated projective A-module; for every finitely generated projective B-module, φ∗(N)\varphi_*(N) is then a finitely generated projective A-module; deduce that there exists a homomorphism of Z\mathbf{Z}-modules φ!:K(B)→K(A)\varphi_! : K(B) \to K(A) such that φ!(χB(N))=χA(φ∗(N))\varphi_!(\chi_B(N)) = \chi_A(\varphi_*(N)). Now prove that one has, for x∈K(A)x \in K(A) and y∈K(B)y \in K(B), φ!(y.φ!(x))=φ!(y).x\varphi_!(y.\varphi^!(x)) = \varphi_!(y).x. If ψ:B→C\psi : B \to C is a second homomorphism of rings for which C is a finitely generated projective B-module, then one has (ψ∘φ)!=φ!∘ψ!(\psi \circ \varphi)_! = \varphi_! \circ \psi_!.

Solution

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Machine translation of the English, by gpt-5-6. Not checked by a person.