Bourbaki

Exercise 24, § 5

Commutative Algebra, II

Let AA be a ring such that Spec(A) is connected.

a) If MM is an a-module projective of rank nn, every direct factor NN of MM not reduced to 0 admits a rank ≤n\leq n.

b) Let uu be a homomorphism of a finite rank projective A-module MM into a finite rank projective A-module M′M', such that u(M)u(M) is a direct factor of M′M'. Now prove that Ker(uu) is then a direct factor of MM (cf. exerc. 23), and one has

rg⁡(Ker⁡(u))+rg⁡(Im⁡(u))=rg⁡(M). \operatorname{rg}(\operatorname{Ker}(u)) + \operatorname{rg}(\operatorname{Im}(u)) = \operatorname{rg}(M).

Moreover the transpose tu^t u is such that tu(M′∗)^t u({M'}^*) is a direct factor of M* and rg⁡(tu(M′∗))=rg⁡(u(M))\operatorname{rg}(^t u({M'}^*)) = \operatorname{rg}(u(M)) (cf. § 3, exerc. 14 a)).

Solution

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Machine translation of the English, by gpt-5-6. Not checked by a person.