Bourbaki

Exercise 14, § 2

Commutative Algebra, III

Let AA be a ring (not necessarily commutative), EE a left AA-module. A topology on EE is said to be linear if it is invariant under translation and if 0 admits a fundamental system of neighbourhoods which are submodules of EE; one then says that EE is linearly topologized. A linear topology on EE is compatible with its additive group structure, and defines on EE a structure of topological AA-module when AA is provided with the discrete topology. On any AA-module, the discrete topology and the least fine topology are linear topologies.

a) If EE is a linearly topologized module, FF a submodule of EE, the topology induced on FF and the quotient topology of that of EE by FF are linear topologies. If (Eα,fαβ)(E_\alpha, f_{\alpha\beta}) is a projective system of linearly topologized AA-modules, where the fαβf_{\alpha\beta} are continuous linear mappings, the topological AA-module E=lim⁡←EαE = \lim \leftarrow E_\alpha is linearly topologized.

b) Let EE be a linearly topologized AA-module. There exists a fundamental system (Vλ)λ∈L(V_\lambda)_{\lambda \in L} of neighbourhoods of 0 in EE, formed of open (and closed) submodules; if φλμ:E/Vμ→E/Vλ\varphi_{\lambda\mu} : E/V_\mu \to E/V_\lambda is the canonical mapping when Vλ⊃VμV_\lambda \supset V_\mu, the family (E/Vλ,φλμ)(E/V_\lambda, \varphi_{\lambda\mu}) is a projective system of discrete AA-modules; the topological AA-module E~=lim⁡←E/Vλ\tilde{E} = \lim \leftarrow E/V_\lambda identifies with the separated completion of EE, which is therefore linearly topologized (Top. gén., chap. III, 3e éd., § 7, no 3).

c) A separated linearly topologized AA-module EE is discrete when it is artinian, or when there exists a smallest element in the set of submodules ≠0\neq 0 of EE.

Solution

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Machine translation of the English, by gpt-5-6-mini. Not checked by a person. That model is a cut down version of the one the rest of this language was written by.