Bourbaki

Exercise 14, § 2

Commutative Algebra, III, 236

Let AA be a ring (not necessarily commutative) and EE a left AA-module. A topology on EE is called linear if it is invariant under translations and 00 admits a fundamental system of neighbourhoods which are submodules of EE; EE is then said to be linearly topologized. A linear topology on EE is compatible with its additive group structure and defines on EE a topological AA-module structure if AA is given the discrete topology. On any AA-module the discrete topology and the coarsest topology are linear topologies.

(a) If EE is a linearly topologized module and FF a submodule of EE, the induce topology on FF and the quotient topology of that on EE by FF are linear topologies. If (Eα,fαβ)(E_\alpha, f_{\alpha\beta}) is an inverse system of linearly topologized AA-modules, where the fαβf_{\alpha\beta} are continuous linear mappings, the topological AA-module E=lim⁡←EαE = \lim \leftarrow E_\alpha is linearly topologized.

(b) Let EE be a linearly topologized AA-module. There exists a fundamental system (Vλ)λ∈L(V_\lambda)_{\lambda \in L} of neighbourhoods of 00 in EE consisting of open (and closed) submodules; if ϕλμ:E/Vμ→E/Vλ\phi_{\lambda\mu}: E/V_\mu \to E/V_\lambda is the canonical mapping when Vλ⊇VμV_\lambda \supseteq V_\mu, the family (E/Vλ,ϕλμ)(E/V_\lambda, \phi_{\lambda\mu}) is an inverse system of discrete AA-modules; the topological AA-module E~=lim⁡←E/Vλ\tilde{E} = \lim \leftarrow E/V_\lambda is identified with the Hausdorff completion of EE, which is therefore linearly topologized (General Topology, Chapter III, § 7, no. 3).

(c) A Hausdorff linearly topologized A-module EE is discrete if it is Artinian or if there exists a least element in the set of submodules ≠0\neq 0 of EE.

Solution

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Transcribed from the printed volume. Not translated.