Bourbaki

Exercise 22, § 2

Commutative Algebra, III

Bourbaki marks this one as harder than the rest.

(a) Let AA be a local ring, m\mathfrak{m} its maximal ideal. Show that if, for a linear topology C\mathscr{C} on AA, AA is strictly linearly compact, C\mathscr{C} is less fine than the m\mathfrak{m}-adic topology.

(b) Let AA be a commutative ring, m\mathfrak{m} an ideal of AA. For AA to be strictly linearly compact for the m\mathfrak{m}-adic topology, it is necessary and sufficient that it be separated and complete for this topology, that A/mA/\mathfrak{m} be an artinian ring and m/m2\mathfrak{m}/\mathfrak{m}^2 a (A/m)(A/\mathfrak{m})-module of finite length (in other words, A is a complete noetherian semi-local ring).

(c) Let I be an infinite set of indices, K a finite field, A=K[[Xi]]i∈IA = K[[X_i]]_{i \in I} the algebra of formal power series with respect to the family of indeterminates (Xi)i∈I(X_i)_{i \in I} (Alg., chap. IV, § 5, exerc. 1); A is a local ring. As a vector space over K, one can identify A with the product space KN(I)K^{N(I)}; if K is provided with the discrete topology and A with the product topology C\mathscr{C}, show that C\mathscr{C} is a linear topology on the ring AA, for which AA is strictly linearly compact; if mm is the maximal ideal of AA, now prove, by reasoning as in exerc. 12 c), that AA is not complete for the mm-adic topology.

Solution

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Machine translation of the English, by gpt-5-mini. Not checked by a person. That model is a cut down version of the one the rest of this language was written by.