Bourbaki

Exercise 22, § 2

Commutative Algebra, III, 241

Bourbaki marks this one as harder than the rest.

(a) Let AA be a local ring and mm its maximal ideal. Show that, if, for a linear topology T\mathscr{T} on AA, AA is strictly linearly compact, T\mathscr{T} is coarser than the mm-adic topology.

(b) Let AA be a commutative ring and mm an ideal of AA. For AA to be strictly linearly compact with the mm-adic topology, it is necessary and sufficient that it be Hausdorff and complete with this topology, that A/mA/m be an Artinian ring and m/m2m/m^2 and (A/m)(A/m)-module of finite length (in other words, AA is a complete Noetherian semi-local ring) *.

(c) Let II be an infinite indexing set, KK a finite field and A=K[[Xi]]i∈IA = K[[X_i]]_{i \in I} the algebra of formal power series in the family of indeterminates (Xi)i∈I(X_i)_{i \in I} (Algebra, Chapter IV, § 5, Exercise 1); AA is a local ring. As a vector space over KK, AA may be identified with the product space KN(I)K^{N(I)}; if KK is given the discrete topology and AA the product topology T\mathscr{T}, show that T\mathscr{T} is a linear topology on the ring AA with which AA is strictly linearly compact; if mm is the maximal ideal of AA, show, by arguing as in Exercise 12 (c), that AA is not complete with the mm-adic topology.

Solution

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Transcribed from the printed volume. Not translated.