Bourbaki

Exercise 14, § 2

Commutative Algebra, IX

Let AA be a complete discrete valuation ring of characteristic zero, whose residue field kk is perfect of characteristic pp. Let KK be the field of fractions of AA. Let nn be an integer ≥1\geq 1 and let ζ\zeta be a primitive pnp^n-th root of unity in KK. Let K‾\overline{K} be an algebraic closure of KK, endowed with the unique valuation vv extending that of KK.

a) Let CC be the Cohen subring of AA, TT its field of fractions; it is a subfield of KK. The canonical isomorphism of W(k)W(k) onto CC induces an isomorphism of W(k)⊗ZQW(k) \otimes_{\mathbf{Z}} \mathbf{Q} onto TT. For every finite degree extension ll of kk, the field W(l)⊗ZQW(l) \otimes_{\mathbf{Z}} \mathbf{Q} is a finite degree extension of W(k)⊗ZQW(k) \otimes_{\mathbf{Z}} \mathbf{Q}, galois if ll is so. If ll is galois, the unique extension TlT_l of TT in K‾\overline{K} isomorphic to W(l)⊗ZQW(l) \otimes_{\mathbf{Z}} \mathbf{Q} has a residue field isomorphic to ll. In particular the field T∞T^\infty, union of the fields TlT_l when ll runs through the galois finite degree extensions of kk (in a fixed algebraic closure of kk), has as residue field an algebraic closure k‾\overline{k} of kk. The same is true of KK. For each extension ll of kk in k‾\overline{k}, we shall denote by TlT_l the unique extension of TT in T∞T^\infty whose residue field is the subfield ll of kk, and by KlK_l the compositum of KK and TlT_l. Then, if ll is galois over kk, KlK_l is galois over KK and its Galois group is canonically identified with the Galois group of ll over kk.

b) Let knk_n be the largest abelian extension of kk in k‾\overline{k} whose galois group is annihilated by pnp^n. By exerc. 19, p. 45, we have a canonical isomorphism

Gal⁡(kn/k)→Hom⁡(Wn(k)/δWn(k),Z/pnZ). \operatorname{Gal}(k_n/k) \to \operatorname{Hom}(W_n(k)/\delta W_n(k), \mathbf{Z}/p^n\mathbf{Z}) .

By A, V, p. 85, th. 4, we have a canonical isomorphism

Gal⁡(Kkn/K)→Hom⁡(Hn/K∗pn,μpn(K)) \operatorname{Gal}(K_{k_n}/K) \to \operatorname{Hom}(H_n/K^{*p^n}, \mu_{p^n}(K))

where Hn=(Kkn∗)pn∩K∗H_n = (K_{k_n}^*)^{p^n} \cap K^*.

Prove that there exists a unique mapping

E∗:Wn(k)/pWn(k)→Hn/K∗pn E^*: W_n(k)/\mathfrak{p}W_n(k) \to H_n/K^{*p^n}

such that the following diagram is commutative:

Gal⁡(Kkn/K)⟶Hom⁡(Hn/K∗pn,μpn(K))↓↓Gal⁡(kn/k)⟶Hom⁡(Wn(k)/pWn(k),Z/pnZ), \begin{array}{ccc} \operatorname{Gal}(K_{k_n}/K) & \longrightarrow & \operatorname{Hom}(H_n/K^{*p^n}, \mu_{p^n}(K)) \\ \downarrow & & \downarrow \\ \operatorname{Gal}(k_n/k) & \longrightarrow & \operatorname{Hom}(W_n(k)/\mathfrak{p}W_n(k), \mathbf{Z}/p^n\mathbf{Z}) , \end{array}

where the right vertical arrow denotes the mapping which associates with the homomorphism φ\varphi of Hn/K∗pnH_n/K^{*p^n} into μpn(K)\mu_{p^n}(K) the homomorphism ψ\psi of Wn(k)/pWn(k)W_n(k)/\mathfrak{p}W_n(k) into Z/pnZ\mathbf{Z}/p^n\mathbf{Z} defined by ζψ(α)=φ(E∗(α))\zeta^{\psi(\alpha)} = \varphi(E^*(\alpha)) for α∈Wn(k)/pWn(k)\alpha \in W_n(k)/\mathfrak{p}W_n(k). The mapping E∗E^* is an isomorphism.

Solution

No solution has been written yet.

Machine translation of the English, by gpt-5-6. Not checked by a person.