Bourbaki

Exercise 1, § 3

Commutative Algebra, IX, p. 75

Let p be a prime number, G the free group on two generators X and Y, Fp[G]F_p[G] the group algebra of G over FpF_p. Put Z=XY−YXZ = XY - YX and denote by α\alpha the two-sided ideal of Fp[G]F_p[G] generated by the elements ZX−XZ,ZY−YZZX - XZ, ZY - YZ and Z2Z^2. Putting A=Fp[G]/αA = F_p[G]/\alpha, denote by z\mathfrak{z} the two-sided ideal of A generated by the image of Z in A (the images of X, Y and Z in A will again be denoted by X, Y, Z). a) Let aa be an element of A. Prove that there exist two families of finite support of elements of FpF_p, say (pα,β)(α,β)∈Z2(p_{\alpha,\beta})_{(\alpha,\beta) \in \mathbf{Z}^2} and (qα,β)(α,β)∈Z2(q_{\alpha,\beta})_{(\alpha,\beta) \in \mathbf{Z}^2}, uniquely determined by the condition

a=∑(α,β)∈Z2(pα,β+qα,βZ)XαYβ. a = \sum_{(\alpha,\beta) \in \mathbf{Z}^2} (p_{\alpha,\beta} + q_{\alpha,\beta}Z) X^\alpha Y^\beta .
Deduce that the quotient algebra A/zA/\mathfrak{z} is commutative and an integral domain, and that the ideal z\mathfrak{z} is contained in the center of A. b) For every pair (a,b)(a, b) of elements of A, there exists an element c of A such that one has
akb−bak=kak−1cZfor every integer k≥0. a^k b - ba^k = ka^{k-1} cZ \quad \text{for every integer } k \geq 0 .
Deduce that the set ApA^p of p-th powers of elements of A is contained in the center of A. c) The multiplicative subset S=A−zS = A - \mathfrak{z} of A admits a calculus of right and left fractions (II, § 2, Exercise 22). Denote by B the ring of fractions of A thus constructed. (To verify, for example, that for every aa in A and every ss in S, there exist b∈Ab \in A and t∈St \in S such that at=sbat = sb, take b=sp−1a,t=spb = s^{p-1} a, t = s^p and use b).) d) Prove that the canonical mapping of A into B is injective. (Observe that the kernel of this mapping is contained in z\mathfrak{z} and reason as in a.).

e) The center of B contains Z. If m is the two-sided ideal of B generated by Z, one has m2=0m^2 = 0. f) The ideal m is the set of non-invertible elements of B, and the field B/m is isomorphic to the field Fp(X,Y)F_p(X, Y). g) Prove that there does not exist a subfield of B whose image in B/m is all of B/m.

In Exercises 2 to 5, the (commutative) topological rings are supposed linearly topologized. If A and B are two topological rings and B is an A-algebra, one says that B is a topological A-algebra if the homomorphism from A into B which defines the algebra structure is continuous.

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Machine translation of the English, by gpt-5.4. Not checked by a person.