Commutative Algebra, IX, p. 80
Let A be an integral domain, A its integral closure. Let a1,...,ar be nonzero elements of A, b the fractional ideal ∑i=1rAai of A. a) There exists a fractional ideal a of A such that aai⊂a for 1≤i≤r. One also has a~ai⊂a~ for 1≤i≤r; we recall (VII, § 1, No. 1) that a~ is the intersection of the principal fractional ideals containing a. b) Let y be a nonzero element of b~. Then
Ay−1⊃i=1⋂rAai−1anda~⊂a~y−1. c) One has
b~⊂A. d) Let
z be an element of
A:Ab. Then
A contains
b~z. e) One has
b⊂A:(A:Ab). f) Let
P be a divisorial ideal of
A and
p=P∩A. Then
p is divisorial in A. (By e), one obtains
p~⊂P. But one also has
p~⊂A.