Bourbaki

Exercise 19, § 4

Commutative Algebra, IX, p. 82

Let AA be a noetherian ring, aa a nonzero ideal of AA. Suppose that AA is separated and complete for the aa-adic topology and that A/aA/a is a Nagata ring. Prove that AA is a Nagata ring. One may reason as follows: a) Suppose that A‾\overline{A} is an integral domain and that for every nonzero prime ideal pp of AA, the ring A/pA/p is Japanese. Let A‾\overline{A} be the integral closure of AA in a finite extension of its field of fractions. Then, for every nonzero prime ideal P\mathfrak{P} of A‾\overline{A}, the ring A‾/P\overline{A}/\mathfrak{P} is a finite algebra over the ring A/(P∩A)A/(\mathfrak{P} \cap A). (Use Exercise 11, a), p. 80.) b) Under the same hypotheses and notations as in a), prove that A‾\overline{A} is noetherian. (Use Exercises 7, p. 79 and 14, p. 81.) Then, arguing as in the preceding exercise, prove that A‾/aA‾\overline{A}/a\overline{A} is a finitely generated AA-module, that A‾\overline{A} is separated for the aA‾a\overline{A}-adic topology, and that A‾\overline{A} is a finitely generated AA-module.

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