Bourbaki

Exercise 3, § 4

Commutative Algebra, IX, p. 78

A ring AA is said to be normal if the ring ApA_p is integrally closed for every prime ideal pp of AA. a) A normal ring AA is reduced, and every prime ideal pp of AA contains only one minimal prime ideal of AA. For every minimal prime ideal pp of AA, the ring A/pA/p is integrally closed. b) A noetherian normal ring AA is isomorphic to a product of a finite number of integrally closed noetherian rings. c) Let AA be a noetherian normal ring and aa an element of AA. Then Ass⁡A(A/aA)\operatorname{Ass}_A(A/aA) contains no embedded prime ideal (IV, § 2, no 3, remark).

EXERCISES

AC IX.79

Solution

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Machine translation of the English, by gpt-5.4. Not checked by a person.