Bourbaki

Exercise 9, § 1

Commutative Algebra, VI

a) Let R be a ring, A a subring of R, x an element of R, S the set of the xk(k⩾0)x^k (k \geqslant 0) in R. Now prove that for x to be integer over A, it is necessary and sufficient that x/1∈A[1/x]x/1 \in A[1/x] in the ring S−1RS^{-1}R. If x is not integer over A, prove that there exists a maximal ideal m of A[1/x]A[1/x] containing 1/x1/x, and that the inverse image of m by the canonical homomorphism A→A[1/x]A \to A[1/x] is a maximal ideal in A.

b) Now prove that the integral closure A′A' of A in R is the intersection of the paravaluative subrings in R (Exercise 8) which contain A. (To see that A′A' is contained in each of these rings, use Exercise 8 a) and Exercise 6 d); to see that if x∈Rx \in R is not integer over A, there exists a subring B of R, paravaluative in R and such that x∉Bx \notin B, use a), Exercise 7 a) and Exercise 8 c), reasoning as in Theorem 3 of No. 3).

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Machine translation of the English, by gpt-5-6-mini. Not checked by a person. That model is a cut down version of the one the rest of this language was written by.