Bourbaki

Exercise 9, § 1

Commutative Algebra, VI, 444

Bourbaki marks this one as harder than the rest.

(a) Let RR be a ring, AA a subring of RR, xx an element of RR and SS the set of xkx^k (k≥0k \geq 0) in RR. Show that, for xx to be integral over AA, it is necessary and sufficient that x/1∈A[1/x]x/1 \in A[1/x] in the ring S−1RS^{-1}R. If xx is not integral over AA, show that there exists a maximal ideal mm of A[1/x]A[1/x] containing 1/x1/x and that the inverse image of mm under the canonical homomorphism A→A[1/x]A \to A[1/x] is a maximal ideal of AA.

(b) Show that the integral closure A′A' of AA in RR is the intersection of the paravaluative subrings of RR (Exercise 8) which contain AA. (To see that A′A' is contained in each of these rings, use Exercise 8 (a) and Exercise 6 (d); to see that, if x∈Rx \in R is not integral over AA, there exists a subring BB of RR which is paravaluative in RR and such that x∉Bx \notin B, use (a), Exercise 7 (a) and Exercise 8 (c), arguing as in Theorem 3 of no. 3.)

Solution

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Transcribed from the printed volume. Not translated.