Bourbaki

Exercise 20, § 3

Commutative Algebra, VII

Let AA be a factorial ring, f=∑k=0nakXkf = \sum_{k=0}^n a_k X^k a polynomial of A[X]A[X]; suppose that there exists an extremal element pp of AA such that : 1°) there exists an index k≤nk \leq n such that aka_k is not divisible by pp, but aia_i is divisible by pp for i<ki < k; 2°) a0a_0 is divisible by pp, but not by p2p^2. Now prove that under these conditions, one of the irreducible factors of ff in A[X]A[X] is of degree ≥k\geq k (reason in (A/pA)[X](A/pA)[X]). Special case where k=nk = n (« Eisenstein irreducibility criterion »).

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Machine translation of the English, by gpt-5-6. Not checked by a person.