Bourbaki

Exercise 8, § 3

Commutative Algebra, VII

Bourbaki marks this one as harder than the rest.

Let AA be an integral ring, x,y,zx, y, z three non-zero elements of A, where x is extremal and Ax∩Ay=AxyAx \cap Ay = Axy. Let S be the multiplicative set of the xnx^n (n≥0n \geq 0), and let B=S−1AB = S^{-1}A; we consider the rings of formal series A[[T]]A[[T]] and B[[T]]B[[T]].

(a) Let i,j,ki, j, k be three integers ⩾0\geqslant 0 such that ijk−ij−jk−ki⩾0ijk - ij - jk - ki \geqslant 0 and zi∈Axj+Aykz^i \in \mathbf{A} x^j + \mathbf{A} y^k. We consider in A[[T]]\mathbf{A}[[T]] the element v=xy−zi−1Tv = xy - z^{i-1} T. Now prove that there exists an integer t>0t > 0 and a series

v′=ytx−1+b1x−2T+⋯+bn−1x−nTn−1+⋯ v' = y^t x^{-1} + b_1 x^{-2} T + \cdots + b_{n-1} x^{-n} T^{n-1} + \cdots
in B[[T]]\mathbf{B}[[T]] such that vv′∈A[[T]]vv' \in \mathbf{A}[[T]] (the bnb_n will be determined by recurrence, proceeding in N\mathbf{N} by intervals of length ijij; inside each interval, take bn+1=bnzi−1x−1b_{n+1} = b_n z^{i-1} x^{-1}; at the end of each interval, use the inequality ijk−ij−jk−ki⩾0ijk - ij - jk - ki \geqslant 0.

(b) Suppose that zi−1∉Ax+Ayz^{i-1} \notin \mathbf{A} x + \mathbf{A} y. Now prove that there exists no formal series in the ring A[[T]]\mathbf{A}[[T]] having constant term yky^k (kk integer >0> 0) and which is an associated element to vv in B[[T]]\mathbf{B}[[T]] (calculate the coefficient of TT in the product of vv and an invertible element of B[[T]]\mathbf{B}[[T]]).

(c) Deduce from a), b) and exerc. 7 an example of a factorial ring A\mathbf{A} such that the ring of formal series A[[T]]\mathbf{A}[[T]] is not factorial. (With the preceding notations, and supposing the conditions of a) and b) on x,y,z,i,j,kx, y, z, i, j, k fulfilled, now prove that vv′vv' cannot be a product of extremal factors uhu_h (1⩽h⩽r1 \leqslant h \leqslant r) in A[[T]]\mathbf{A}[[T]]; one will observe that the uhu_h are formal series whose constant terms are powers of yy. Consider next the ring C=S′−1A[[T]]\mathbf{C} = {S'}^{-1} \mathbf{A}[[T]], where S′S' is formed of the series whose constant term is in SS; B[[T]]\mathbf{B}[[T]] is the completion of the Zariski ring C\mathbf{C}; now prove that v′∈Cv' \in \mathbf{C}, and that vv and the uhu_h are extremal in C\mathbf{C}; obtain finally a contradiction with b)).

(d) Deduce from c) an example of a local factorial noetherian ring A\mathbf{A} whose completion A^\hat{\mathbf{A}} is a Krull ring which is not factorial.

Solution

No solution has been written yet.

Machine translation of the English, by gpt-5-6-mini. Not checked by a person. That model is a cut down version of the one the rest of this language was written by.