Bourbaki marks this one as harder than the rest.
Let A be an integral domain and x,y,z three non-zero elements of A, where x is extremal and Ax∩Ay=Axy. Let S be the multiplicative set of the xn (n≥0) and let B=S−1A; consider the domains of formal power series A[[T]] and B[[T]]. (a) Let i,j,k be three integers ≥0 such that ijk−ij−jk−ki≥0 and zi∈Axj+Ayk. Consider in A[[T]] the element v=xy−zi−1T. Show that there exists an integer t>0 and a series
v′=ytx−1+b1x−2T+⋯+bn−1x−nTn−1+⋯ in
B[[T]] such that
vv′∈A[[T]] (determine the
bn inductively, proceeding in
N by intervals of length
ij; in the interior of each interval, take
bn+1=bnzi−1x−1; at the end of each interval, use the inequality
ijk+ij−jk−ki≥0. (b) Suppose that
zi−1∈/Ax+Ay. Show that there exists in the ring
A[[T]] no formal power series of constant term
yk (
k an integer
>0) and which is an element associated with
v in
B[[T]] (calculate the coefficient of
T in the product of
v and an invertible element of
B[[T]]).
(c) Deduce from (a), (b) and Exercise 7 an example of a factorial domain A such that the domain of formal power series A[[T]] is not factorial. (In the above notation and assuming that the conditions of (a) and (b) on x,y,z,i,j,k are fulfilled, show that vv′ cannot be a product of extremal factors uh (1≤h≤r) in A[[T]]; observe that the uh are formal power series whose constant terms are powers of y. Then consider the ring C=S′−1A[[T]], where S′ consists of the series whose constant term is in S; B[[T]] is the completion of the Zariski ring C; show that v′∈C and that v and the uh are extremal in C; obtain finally a contradiction with (b).)
(d) Deduce from (c) an example of a Noetherian factorial local integral domain A whose completion A^ is a non-factorial Krull domain.