Bourbaki

Exercise 2, § 6

Commutative Algebra, VIII, p. 99

Let AA be a ring, and F=(Fi)i∈Z\mathscr{F} = (\mathscr{F}_i)_{i \in \mathbf{Z}} a decreasing filtration of A such that Fi=A\mathscr{F}_i = A for i≤0i \leq 0. Let A\mathscr{A} be the subring ⨁i∈ZFi.v−i\bigoplus_{i \in \mathbf{Z}} \mathscr{F}_i . v^{-i} of A[v,v−1]A[v, v^{-1}] and let grF(A)\mathrm{gr}_{\mathscr{F}}(A) be the graded ring associated with the filtered ring (A, F\mathscr{F}). (a) Prove that the homomorphism f:A→grF(A)f : \mathscr{A} \to \mathrm{gr}_{\mathscr{F}}(A) defined by f(∑iaiv−i)=∑ia‾if(\sum_i a_i v^{-i}) = \sum_i \overline{a}_i, where a‾i\overline{a}_i is the class of aia_i in Fi/Fi+1\mathscr{F}_i / \mathscr{F}_{i+1}, induces an isomorphism of A/v.A\mathscr{A}/v.\mathscr{A} with grF(A)\mathrm{gr}_{\mathscr{F}}(A). (b) Prove that for every invertible element v0v_0 in A, the homomorphism ev0:A→Ae_{v_0} : \mathscr{A} \to A defined by

ev0(∑aiv−i)=∑aiv0−i e_{v_0}(\sum a_i v^{-i}) = \sum a_i v_0^{-i}
induces an isomorphism of A/(v−v0)A\mathscr{A}/(v - v_0) \mathscr{A} with A. (c) Prove that A/A[v]\mathscr{A}/A[v] is a A[v]A[v]-module of torsion. (d) Assuming now that A contains a field k, prove that the composed morphism
k[v]→A[v]→A(where A[v]=⨁i≤0Fi.v−i) k[v] \to A[v] \to \mathscr{A} \quad (\text{where } A[v] = \bigoplus_{i \leq 0} \mathscr{F}_i . v^{-i})
makes A\mathscr{A} a k[v]k[v]-module without torsion. Deduce that A\mathscr{A} is a k[v]k[v]-module flat. (e) Suppose that A is local, with maximal ideal mm, and contains a field kk such that A is direct sum of kk and mm (as additive group). Prove that there exists an ideal S of A\mathscr{A} such that A\mathscr{A} is direct sum of k[v]k[v] and S (we have set Fi=mi\mathscr{F}_i = m^i for every i∈Zi \in \mathbf{Z}).

Solution

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Machine translation of the English, by gpt-5-mini. Not checked by a person. That model is a cut down version of the one the rest of this language was written by.