Bourbaki

Exercise 6, § 6

Commutative Algebra, VIII, p. 100

Bourbaki marks this one as harder than the rest.

Let ρ:A→B\rho : A \to B be an injective homomorphism of noetherian rings, making BB an AA-algebra of finite type. Let qq be a prime ideal of BB distinct from BB, and put p=ρ−1(q)p = \rho^{-1}(q). a) Now prove that one has, with the notations of the preceding exercise, the inequality

(∗)ht(q)+dA/p(B/q)⩽ht(p)+dA(B). (*) \quad \mathrm{ht}(q) + d_{A/p}(B/q) \leqslant \mathrm{ht}(p) + d_A(B) .
(One may proceed by induction on dA(B)d_A(B).) b) Now prove that if the AA-algebra BB is generated by dd elements and dA(B)=dd_A(B) = d, there is equality in (). c) Now prove that if AA is integral and such that the polynomial ring A[T1,...,Tn]A[T_1, ..., T_n] is catenary for every nn, there is equality in () for every integral AA-algebra of finite type BB and every prime ideal qq of BB distinct from BB.

Solution

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Machine translation of the English, by gpt-5-mini. Not checked by a person. That model is a cut down version of the one the rest of this language was written by.