Exercise 10, § 4
Commutative Algebra, X, p. 164
Bourbaki marks this one as harder than the rest.
Let be a noetherian ring, a finitely generated -module. For every integer , denote by the set of elements of such that . Let be an integer . (a) In order that satisfy the property (, exer. 8), it is necessary and sufficient that one have for every . (b) Suppose that is closed in for every . Let be an element of . In order that the -module satisfy the property (, exer. 8), it is necessary and sufficient that one have for every and every component of containing . (c) Suppose that the ring is presentable. Deduce from (b) that the set of prime ideals of such that satisfies the property is open in .
Solution
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