Bourbaki

Exercise 13, § 4

Commutative Algebra, X

Bourbaki marks this one as harder than the rest.

Let pp be a prime number, qq a power of pp, and AA a reduced noetherian local ring of characteristic pp. Denote by AqA^q the subring of AA formed by the elements aqa^q for a∈Aa \in A. Prove that for AA to be regular, it is necessary and sufficient that the AqA^q-module AA be flat.

(One reduces to the case where AA is complete, hence a quotient of an algebra of formal power series B=κA[[X1,…,Xn]]B = \kappa_A[[X_1, \ldots, X_n]] by an ideal bb, which one may suppose contained in mB2m_B^2. If AA is regular, one has b=0b = 0. If AA is flat over AqA^q, let xix_i be the image of XiX_i in AA; prove that the family (x1q,…,xnq)(x_1^q, \ldots, x_n^q) is A-independent (exerc. 12), and deduce the equality lg⁡A(A/(x1q,…,xnq))=qn\lg_A(A/(x_1^q, \ldots, x_n^q)) = q^n. Show that this entails b⊂(X1qs,…,Xnqs)b \subset (X_1^{q^s}, \ldots, X_n^{q^s}); prove analogously that one has b⊂(X1qs,…,Xnqs)b \subset (X_1^{q^s}, \ldots, X_n^{q^s}) for every s, whence finally b=0b = 0.)

Solution

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Machine translation of the English, by gpt-5-6. Not checked by a person.