Bourbaki

Exercise 7, § 4

Commutative Algebra, X

Bourbaki marks this one as harder than the rest.

Let AA be a regular local ring of dimension 3, ff a nonzero element of mAm_A. Prove that the following conditions are equivalent:

(i) the ring A/(f)A/(f) is not factorial; (ii) there exists an integer n⩾2n \geqslant 2 and a matrix X∈Mn(A)X \in M_n(A), with elements in mAm_A, such that f=det⁡(X)f = \det(X).

(Under assumption (ii), prove that the ideal of A/(f)A/(f) generated by the classes of the minors X11,…,X1nX^{11}, \ldots, X^{1n} of XX, where X1pX^{1p} is obtained by deleting the first row and the column of index pp, has height 1 but is not principal. Under assumption (i), let p\mathfrak{p} be a prime ideal of height 2 of AA whose image in A/(f)A/(f) is not principal; deduce from Exercise 11 of § 3 that p\mathfrak{p} is generated by the minors of order n−1n-1 of a matrix Y∈Mn,n−1(A)Y \in M_{n,n-1}(A) with elements in mAm_A. Write ff as the determinant of a matrix Y~\tilde{Y} obtained by adding a column YnY_n to YY; if an element of YnY_n is invertible reduce to the case where YnY_n belongs to the canonical basis of AnA^n.)

Solution

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Machine translation of the English, by gpt-5-6-mini. Not checked by a person. That model is a cut down version of the one the rest of this language was written by.