Bourbaki

Exercise 2, § 9

Commutative Algebra, X

Let AA be a regular local ring, II an ideal of AA, BB the ring A/IA/I; suppose that BB is a Macaulay ring. Let (L,p)(L, p) be a minimal projective resolution of the AA-module BB; it is of length c=ht(I)c = \mathrm{ht}(I). (a) Let L∗L^* be the complex HomgrA(L,A)\mathrm{Homgr}_A(L, A); prove that one has Hi(L∗)=0H^i(L^*) = 0 for i≠ci \neq c and that the BB-module Hc(L∗)H^c(L^*) is dualizing. (b) Prove that the following conditions are equivalent: (i) AA is a Gorenstein ring ; (ii) the complexes LL and L∗(−d)L^*(-d) are isomorphic ; (iii) LcL_c is free of rank one.

Solution

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Machine translation of the English, by gpt-5-6-mini. Not checked by a person. That model is a cut down version of the one the rest of this language was written by.