Bourbaki

Exercise 8, § 9

Commutative Algebra, X

Let AA be a local Gorenstein ring, aa a nonzero ideal of height zero, and bb the annihilator of aa.

a) Prove that the ideal bb is of height zero, and that the AA-module A/bA/b has no immersed associated prime ideals (observe that every associated prime ideal of A/bA/b is associated to AA).

b) Suppose that the AA-module A/aA/a has no immersed associated prime ideals; prove that aa is the annihilator of bb (reduce to the case where dim⁡(A)=0\dim(A) = 0, and use Matlis duality).

c) For A/aA/a to be a Macaulay ring, it is necessary and sufficient that the same be true of A/bA/b (use the cor. of th. 1 and that of prop. 3). If these conditions are satisfied, the A/aA/a-module bb is dualizing.

Solution

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Machine translation of the English, by gpt-5-6-mini. Not checked by a person. That model is a cut down version of the one the rest of this language was written by.