Bourbaki

Exercise 20, § 6

Algebra, I, p. 138

Let G be a finite commutative group, written additively. Let x=∑g∈Ggx = \sum_{g \in G} g, and let G2G_2 be the subgroup of G formed by the elements gg such that 2g=02g = 0. a) Now prove that x=∑g∈G2gx = \sum_{g \in G_2} g. b) Now prove that x=0x = 0 if Card(G2G_2) ≠2\neq 2. If Card(G2G_2) = 2, now prove that xx is the unique nonzero element of G2G_2. c) Now prove that Card(G2G_2) = 2 if and only if the 2-Sylow subgroup of G is cyclic and ≠0\neq 0. d) \* Let pp be a prime number. Now prove that

(p−1)!≡−1(modp). (p - 1)! \equiv -1 \pmod{p}.
(Apply b) to the multiplicative group of the field Z/pZ\mathbf{Z}/p\mathbf{Z}.)*

Solution

No solution has been written yet.

Machine translation of the English, by gpt-5-mini. Not checked by a person. That model is a cut down version of the one the rest of this language was written by.