Bourbaki

Exercise 32, § 6

Algebra, I, p. 140

Bourbaki marks this one as harder than the rest.

Let pp be a prime number and let G be a pp-group. Let G∗=GpD(G)G^* = G^p D(G) be the subgroup of G generated by D(G) and by the xpx^p for x∈Gx \in G. a) Prove that G∗G^* is the intersection of the kernels of the homomorphisms of G into Z/pZ\mathbf{Z}/p\mathbf{Z}. b) Prove that a subset S of G generates G if and only if the image of S in G/G∗G/G^* generates G/G∗G/G^*. Deduce that, if (G:G∗)=pn(G:G^*) = p^n, the integer nn is the minimum number of elements of a subset of G generating G; in particular, G is cyclic if and only if n⩽1n \leqslant 1. c) Let uu be an automorphism of G of order prime to pp and let uˉ\bar{u} be the corresponding automorphism of G/G∗G/G^*. Prove that uˉ=1\bar{u} = 1 entails u=1u = 1.

Solution

No solution has been written yet.

Machine translation of the English, by gpt-5-6-mini. Not checked by a person. That model is a cut down version of the one the rest of this language was written by.