Exercise 39, § 6
Algebra, I, p. 142
Bourbaki marks this one as harder than the rest.
Let G be a finite group, , a prime number, X the set of the -Sylow subgroups of G, and . Then G operates transitively on X by conjugation; let , be the corresponding homomorphism (we write A B for the relation “A is isomorphic to B”), and let K be its kernel. a) Prove that K is the intersection of the normalizers of the P X, and that the -Sylow subgroup of K is the intersection of the P X. Deduce that if the order k of K divides . b) Prove that if G has no subgroup of index 2, then , and that if (resp. ), then (resp. ). c) Using a) and b), as well as the preceding exercise, prove the following facts: If , and if a 3-Sylow subgroup of G is not distinguished, then G . If , and if G does not have the property (ST), then G . If , then G has the property (ST). (Prove that if a 3-Sylow subgroup of G is not distinguished, then G contains a subgroup K of order 3, such that G/K , and that K is central.) If , and if G does not have the property (ST), then G contains a distinguished subgroup K of order 2 such that G/K . If , and if G does not have the property (ST), then G . (Prove that such a group G has no distinguished subgroup of order 5, nor of order 2, nor of index 2. Deduce that G is isomorphic to a subgroup of , and by reasoning as in exerc. 25 of I, p. 133, that G .) If , and if a 3-Sylow subgroup of G is not distinguished, then G contains a distinguished subgroup K such that G/K is isomorphic either to , or to . If , and if a 2-Sylow subgroup of G is not distinguished, then G contains a distinguished subgroup K such that G/K . d) Prove that a group G of order is solvable except if G .
Solution
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