Bourbaki

Exercise 39, § 6

Algebra, I, 158

Bourbaki marks this one as harder than the rest.

Let G be a finite group, n=Card(G)n = \mathrm{Card}(G), pp a prime number, X the set of Sylow pp-subgroups of G and r=Card(X)r = \mathrm{Card}(X). Then G operates transitively on X by conjugation; let ϕ:G→SX≈Sr\phi : G \to \mathfrak{S}_X \approx \mathfrak{S}_r be the corresponding homomorphism (A ≈\approx B denotes the relation "A is isomorphic to B") and K its kernel.

(a) Show that K is the intersection of the normalizers of the P∈XP \in X and that the Sylow pp-subgroup of K is the intersection of the P∈XP \in X. Deduce that if r>1r > 1 the order kk of K divides n/rpn/rp.

(b) Show that if G has no subgroup of index 2, then ϕ(G)⊂AX\phi(G) \subset \mathfrak{A}_X and that if n=kr!n = kr! (resp. 12kr!\frac{1}{2}kr!), then ϕ(G)=SX\phi(G) = \mathfrak{S}_X (resp. AX\mathfrak{A}_X).

(c) Using (a), (b) and the preceding exercise, show the following facts: If n=12n = 12 and a Sylow 3-subgroup of G is not normal, then G≈A4G \approx \mathfrak{A}_4. If n=24n = 24 and G does not have property (ST), then G≈S4G \approx \mathfrak{S}_4. If n=36n = 36, then G has property (ST). (Show that if a Sylow 3-subgroup of G is not normal, then G contains a subgroup K of order 3 such that G/K≈A4G/K \approx \mathfrak{A}_4 and that K is central.) If n=48n = 48 and G does not have property (ST), then G contains a normal subgroup K of order 2 such that G/K≈S4G/K \approx \mathfrak{S}_4. If n=60n = 60 and G does not have property (ST), then G≈A5G \approx \mathfrak{A}_5. (Show that such a group G has no normal subgroup of order 5, nor of order 2, nor of index 2. Deduce that G is isomorphic to a subgroup of S6\mathfrak{S}_6 and, arguing as in Exercise 25 of § 5, that G≈A5G \approx \mathfrak{A}_5.)

If n=72n = 72 and a Sylow 3-subgroup of GG is not normal, then GG contains a normal subgroup KK such that G/KG/K is isomorphic either to S4\mathfrak{S}_4 or to A4\mathfrak{A}_4.

If n=96n = 96 and a Sylow 2-subgroup of GG is not normal, then GG contains a normal subgroup KK such that G/K≈S3G/K \approx \mathfrak{S}_3.

(d) Show that a group GG of order ≤100\leq 100 is solvable unless G≈A5G \approx \mathfrak{A}_5.

Solution

No solution has been written yet.

Transcribed from the printed volume. Not translated.