Bourbaki

Exercise 14, § 10

Algebra, II, p. 208

Bourbaki marks this one as harder than the rest.

Let EE be a vector space of dimension ⩾2\geqslant 2 over a field KK. a) Show that the projective group PGL(E)\mathbf{PGL}(E) is canonically isomorphic to the quotient of the linear group GL(E)\mathbf{GL}(E) by its center (isomorphic to the multiplicative group of the center of KK, cf. II, p. 182, exerc. 26). b) Let PSL(E)\mathbf{PSL}(E) denote the canonical image of the group SL(E)\mathbf{SL}(E) (exerc. 13) in PGL(E)\mathbf{PGL}(E); it is a normal subgroup of PGL(E)\mathbf{PGL}(E), containing the commutator group of PGL(E)\mathbf{PGL}(E) when EE is of finite dimension. Show that PSL(E)\mathbf{PSL}(E) is a doubly transitive group (I, p. 131, exerc. 14) of permutations of P(E)\mathbf{P}(E). c) Let a≠0a \neq 0 be an element of EE, and let e=π(a)∈P(E)e = \pi(a) \in \mathbf{P}(E) (with the notations of II, p. 133). Show that the transvections of the form x↦x+aφ(x)x \mapsto x + a \varphi(x) (where φ∈E∗\varphi \in E^* is such that φ(a)=0\varphi(a) = 0) constitute a commutative subgroup of SL(E)\mathbf{SL}(E); if Γe\Gamma_e is the image of this subgroup in PSL(E)\mathbf{PSL}(E), Γe\Gamma_e is a normal subgroup of the subgroup Φe\Phi_e of PSL(E)\mathbf{PSL}(E) leaving ee invariant. Show moreover that the union of the conjugate subgroups of Γe\Gamma_e in PSL(E)\mathbf{PSL}(E) generates PSL(E)\mathbf{PSL}(E). d) Let Σ\Sigma be a primitive group (I, p. 131, exerc. 13) of permutations of a set FF, which is equal to its commutator group. Suppose that there exists an element c∈Fc \in F such that the subgroup Φc\Phi_c of Σ\Sigma leaving cc invariant contains a commutative normal subgroup Γc\Gamma_c, such that the union of the conjugate subgroups of Γc\Gamma_c in Σ\Sigma generates Σ\Sigma. Show that under these conditions Σ\Sigma is simple. (Let Δ\Delta be a normal subgroup of Σ\Sigma distinct from the identity; using I, p. 131, exerc. 17, show that one has Σ=Δ.Φc=Δ.Γc\Sigma = \Delta . \Phi_c = \Delta . \Gamma_c, and using the fact that Γc\Gamma_c is commutative, deduce that every commutator in Σ\Sigma is contained in Δ\Delta.) e) Deduce from c), d) and exerc. 13 c) that the group PSL(E)\mathbf{PSL}(E) is simple unless dim⁡E=2\dim E = 2 and KK has 2 or 3 elements. f) If dim⁡E=n+1\dim E = n + 1 and if KK is a field with qq elements, show that the order of PGL(E)\mathbf{PGL}(E) is

(qn+1−1)(qn+1−q)…(qn+1−qn−1)qn (q^{n+1} - 1)(q^{n+1} - q) \ldots (q^{n+1} - q^{n-1}) q^n
(use a), exerc. 9 a) of II, p. 202, and the fact that KK is necessarily commutative (V, § 11, exerc. 14 and VIII, § 11, no. 1, th. 1)). g) Show that if dim⁡E=2\dim E = 2 and if KK is a field with 2 (resp. 3) elements, PSL(E)\mathbf{PSL}(E) is isomorphic to the symmetric group S3S_3 (resp. to the alternating group A4A_4). (Considering PSL(E)\mathbf{PSL}(E) as a permutation group of P(E)\mathbf{P}(E), remark that it contains every transposition (resp. every cycle (a b c)(a\ b\ c)) and use f)). h) Show that, except in the cases considered in g), every normal subgroup of SL(E)\mathbf{SL}(E) distinct from SL(E)\mathbf{SL}(E) is contained in the center of SL(E)\mathbf{SL}(E) (use d) and the fact that every transvection is a commutator in SL(E)\mathbf{SL}(E) (exerc. 13 c))).

Solution

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Machine translation of the English, by gpt-5-6-mini. Not checked by a person. That model is a cut down version of the one the rest of this language was written by.