Bourbaki

Exercise 14, § 10

Algebra, II, 421

Bourbaki marks this one as harder than the rest.

Let E be a vector space of dimension ⩾2\geqslant 2 over a field K.

(a) Show that the projective group PGL(E)\mathbf{PGL}(E) is canonically isomorphic to the quotient of the linear group GL(E)\mathbf{GL}(E) by its centre (isomorphic to the multiplicative group of the centre of K, cf. § 1, Exercise 26).

(b) Let PSL(E)\mathbf{PSL}(E) denote the canonical image of the group SL(E)\mathbf{SL}(E) in PGL(E)\mathbf{PGL}(E); it is a normal subgroup of PGL(E)\mathbf{PGL}(E), containing the commutator group of PGL(E)\mathbf{PGL}(E) when EE is finite-dimensional. Show that PSL(E)\mathbf{PSL}(E) is a doubly transitive (cf. I, § 5, Exercise 14) group of permutations of P(E)\mathbf{P}(E).

(c) Let a≠0a \neq 0 be an element of EE and let e=π(a)∈P(E)e = \pi(a) \in \mathbf{P}(E) (in the notation of § 9, no. 6). Show that the transvections of the form x↦x+aϕ(x)x \mapsto x + a \phi(x) (where ϕ∈E∗\phi \in E^* is such that ϕ(a)=0\phi(a) = 0) constitute a commutative subgroup of SL(E)\mathbf{SL}(E); if Γe\Gamma_e is the image of this subgroup in PSL(E)\mathbf{PSL}(E), Γe\Gamma_e is a normal subgroup of the subgroup Φe\Phi_e of PSL(E)\mathbf{PSL}(E) leaving ee invariant. Show also that the union of the subgroups conjugate to Γe\Gamma_e in PSL(E)\mathbf{PSL}(E) generates PSL(E)\mathbf{PSL}(E).

(d) Let Σ\Sigma be a primitive group (I, § 5, Exercise 13) of permutations of a set FF which is equal to its commutator group. Suppose that there exists an element c∈Fc \in F such that the subgroup Φc\Phi_c of Σ\Sigma leaving cc invariant contains a commutative normal subgroup Γc\Gamma_c such that the union of the subgroups conjugate to Γc\Gamma_c in Σ\Sigma generates Σ\Sigma. Show that under these conditions Σ\Sigma is simple. (Let Δ\Delta be a normal subgroup of Σ\Sigma distinct from the identity; using I, § 5, Exercise 17, show that Σ=Δ.Φc=Δ.Γc\Sigma = \Delta . \Phi_c = \Delta . \Gamma_c and, using the fact that Γc\Gamma_c is commutative, deduce that every commutator in Σ\Sigma is contained in Δ\Delta.)

(e) Deduce from (c), (d) and Exercise 13(c) that the group PSL(E)\mathbf{PSL}(E) is simple except when dim⁡E=2\dim E = 2 and KK has 2 or 3 elements.

(f) If dim⁡E=n+1\dim E = n + 1 and KK is a field with qq elements, show that the order of PGL(E)\mathbf{PGL}(E) is

(qn+1−1)(qn+1−q)…(qn+1−qn−1)qn (q^{n+1} - 1)(q^{n+1} - q)\ldots(q^{n+1} - q^{n-1})q^n
(use (a), Exercise 9(a) of § 9, and the fact that KK is necessarily commutative (V, § 11, Exercise 14 and VIII, § 11, no. 1, Theorem 1)).*

(g) Show that if dim⁡E=2\dim E = 2 and KK is a field with 2 (resp. 3) elements, PSL(E)\mathbf{PSL}(E) is isomorphic to the symmetric group S3S_3 (resp. the alternating group A4A_4). (Considering PSL(E)\mathbf{PSL}(E) as a group of permutations of P(E)\mathbf{P}(E), note that it contains every transposition (resp. every cycle (a b c)(a\ b\ c) and use f).)

(h) Show that, except in the cases considered in (g), every normal subgroup of SL(E)\mathbf{SL}(E) distinct from SL(E)\mathbf{SL}(E) is contained in the centre of SL(E)\mathbf{SL}(E) (use (d) and the fact that every transvection is a commutator in SL(E)\mathbf{SL}(E) (Exercise 13(c))).

Solution

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Transcribed from the printed volume. Not translated.