Exercise 15, § 10
Algebra, II, p. 208
Bourbaki marks this one as harder than the rest.
Let be a ring; for every integer , we identify canonically with the submodule of formed by the elements whose coordinates of index are 0, and we denote by the supplementary submodule formed by the elements whose coordinates of index are 0. We identify every endomorphism with the automorphism of
A^{(N)} whose restriction to A^n is u and whose restriction to A'_n is the identity, so that is identified with a subgroup of ; we denote by F the subgroup of union of the , in other words the subgroup leaving invariant all but a finite number of the elements of the canonical basis of (cf. II, p. 207, exerc. 12). Let T_n be the subgroup of generated by the for (II, p. 161), and let T be the subgroup of F union of the T_n. (a) Now prove that for , T_n is equal to its commutator group. (b) Let a, b be two invertible elements of A. Now prove that one has:
where P, Q, P', Q' belong to T_2. Deduce that the matrix belongs to T_2. (c) Deduce from b) that the commutator group of is contained in T_{2n} (replace A by in b)). Conclude (using a)) that the commutator group of F is equal to T.
Solution
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