Exercise 15, § 10
Algebra, II, 422
Bourbaki marks this one as harder than the rest.
Let be a ring; for every integer , is canonically identified with the submodule of consisting of the elements whose coordinates of index are 0 and denotes the complementary submodule consisting of the elements whose coordinates of index are 0. Every endomorphism is identified with the automorphism of whose restriction to is and whose restriction to is the identity, so that is identified with a subgroup of ; let denote the subgroup of the union of the , in other words the subgroup leaving invariant the elements of the canonical basis of except for a finite number of them (cf. Exercise 12).
Let be the subgroup of generated by the for (no. 13) and let be the subgroup of the union of the .
(a) Show that for is equal to its commutator group. (b) Let be two invertible elements of . Show that
(c) Deduce from (b) that the commutator group of is contained in (replace by in (b)). Conclude (using (a)) that the commutator group of is equal to .
Solution
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