Bourbaki

Exercise 14, § 2

Algebra, II, p. 185

Let AA be a ring. Now prove that for every AA-module MM, there exists an AA-module injective II such that MM is isomorphic to a submodule of II. (Apply Exercise 13 d) with C=ZC = \mathbf{Z}, using Exercise 11 b) and the fact that every AA-module is quotient of a free AA-module.)

Solution

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Machine translation of the English, by gpt-5-6-mini. Not checked by a person. That model is a cut down version of the one the rest of this language was written by.