Bourbaki

Exercise 24, § 1

Integration, VII

Bourbaki marks this one as harder than the rest.

a) In R\mathbf{R}, let AA (resp. BB) be the set of numbers xx whose proper dyadic expansion x=x0+∑i=1∞xi2−ix = x_0 + \sum_{i=1}^\infty x_i 2^{-i} (x0x_0 integer, xi=0x_i = 0 or xi=1x_i = 1 for i≥1i \geq 1) is such that xi=0x_i = 0 for ii even >0> 0 (resp. ii odd). Prove that, for Lebesgue measure, AA and BB are of measure zero, but A+B=RA + B = \mathbf{R}.

b) Deduce from a) that there exists a basis HH of R\mathbf{R} (over Q\mathbf{Q}) contained in A∪BA \cup B, hence of measure zero. The set P1P_1 of the numbers rhrh, where r∈Qr \in \mathbf{Q} and h∈Hh \in H, is also of measure zero.

c) Let PnP_n denote the set of real numbers for which at most nn coordinates relative to the basis HH are non-zero. Prove that if PnP_n is negligible and if Pn+1P_{n+1} is measurable, then Pn+1P_{n+1} is negligible. (Let h0∈Hh_0 \in H; first prove that the set SS of the x∈Pn+1x \in P_{n+1} whose coordinate relative to h0h_0 is ≠0\neq 0, is negligible. Using exerc. 20, prove that, if Pn+1P_{n+1} were not negligible, there would exist two distinct points x′,x′′x', x'' of Pn+1∩CSP_{n+1} \cap \mathbf{C} S such that (x′−x′′)/h0(x' - x'')/h_0 is rational, and deduce a contradiction).

d) Deduce from a) and b) that there exist in R\mathbf{R} two negligible sets C, D such that C + D is not measurable.

Solution

No solution has been written yet.

Machine translation of the English, by gpt-5-6-mini. Not checked by a person. That model is a cut down version of the one the rest of this language was written by.