Bourbaki

Exercise 29, § 1

Integration, VII

Bourbaki marks this one as harder than the rest.

a) Let pp be a prime number; there exist two integers a,ba, b such that a2+b2+1≡0a^2 + b^2 + 1 \equiv 0 (mod. pp) (Alg., chap. V, § 11, No. 5, cor. of the theorem 3). Now prove that there exist integers x1,x2,x3,x4x_1, x_2, x_3, x_4 not all zero such that ax1+bx2≡x3ax_1 + bx_2 \equiv x_3 (mod. pp), bx1−ax2≡x4bx_1 - ax_2 \equiv x_4 (mod. pp) and

y=x12+x22+x32+x42≤2 p y = x_1^2 + x_2^2 + x_3^2 + x_4^2 \leq \sqrt{2}\ p

(same method as in Exercise 28 c)). Now prove that yy is divisible by pp, and deduce that y=py = p.

b) Deduce from a) that every integer n≥0n \geq 0 is the sum of at most four squares (Lagrange's theorem) ; use Alg., chap. IV, § 2, Exercise 11).

Solution

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Machine translation of the English, by gpt-5-mini. Not checked by a person. That model is a cut down version of the one the rest of this language was written by.