Bourbaki

Exercise 29, § 1

Integration, VII, p. 87

Bourbaki marks this one as harder than the rest.

a) Let pp be a prime number; there exist two integers a,ba, b such that a2+b2+1≡0(modp)a^2 + b^2 + 1 \equiv 0 \pmod{p} (Alg., Ch. V, 1st edn., §11, No. 5, Cor. of Th. 3). Show that there exist integers x1,x2,x3,x4x_1, x_2, x_3, x_4 not all zero such that ax1+bx2≡x3(modp)ax_1 + bx_2 \equiv x_3 \pmod{p}, bx1−ax2≡x4(modp)bx_1 - ax_2 \equiv x_4 \pmod{p} and

y=x12+x22+x32+x42≤2p y = x_1^2 + x_2^2 + x_3^2 + x_4^2 \leq \sqrt{2} p
(same method as in Exer. 28 c)). Show that yy is divisible by pp, and deduce therefrom that y=py = p.

b) Deduce from a) that every integer n≥0n \geq 0 is the sum of four squares (Lagrange’s theorem; make use of Alg., Ch. IV, 1st edn., §2, Exer. 11).

Solution

No solution has been written yet.

Transcribed from the printed volume. Not translated.