Bourbaki

Exercise 9, § 5

Tag 0400, permanent. Cite it as [Bourbaki, Tag 0400].

Algebraic Topology, III, p. 338

Let us take up again the notations of exercise 6. For every integer n∈N∗n\in \mathbf{N}^*, let cn:I→Cnc_n:\mathbf{I}\rightarrow C_n be the loop at the origin defined by t↦12n(1−t\mapsto \frac{1}{2n}(1- cos(2πt\pi t), sin(2πt\pi t)).

(a) For every sequence α∈{0,1}N∗\alpha \in \{0,1\}^{\mathbf{N}^*}, let cαc_{\alpha} be the mapping defined by cα(0)=0c_{\alpha}(0) = 0 by cα(t)=αncn(2nt−1)c_{\alpha}(t) =\alpha_nc_n(2^nt-1) for every integer n⩾1n\geqslant 1 and every t∈It\in \mathbf{I} such that 2−n⩽2^{-n}\leqslant t⩽21−nt\leqslant 2^{1-n}. Show that it is a loop at the origin. Show that the mapping α↦[cα]\alpha \mapsto [c_{\alpha}] from {0,1}N∗\{0,1\}^{\mathbf{N}^*} into π1(P,0)\pi_1(P,0) is injective.

(b) For every integer n⩾1n\geqslant 1, let qnq_n be the mapping from P into CnC_n given by qn(x)=xq_n(x) =x if x∈Cnx\in C_n and qn(x)=0q_n(x) = 0 otherwise. It is continuous. Show that the group homomorphism ψ:π1(P,0)→∏n⩾1π1(Cn,0)\psi :\pi_1(P,0)\rightarrow \prod_{n\geqslant 1}\pi_1(C_n,0) given by ψ(γ)=((qn)∗(γ))n\psi (\gamma ) = ((q_n)_*(\gamma ))_n admits a section.

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Machine translation of the English, by gpt-5-mini. Not checked by a person. That model is a cut down version of the one the rest of this language was written by.