Bourbaki

Exercise 6, § 7

General Topology, III, p. 86

Bourbaki marks this one as harder than the rest, it is set in small type as supplementary.

Let (Gn,fnm)n∈N(G_n, f_{nm})_{n \in \mathbf{N}} be the projective system of compact groups such that Gn=T=R/ZG_n = \mathbf{T} = \mathbf{R}/\mathbf{Z} for every nn, and fnmf_{nm} is the continuous homomorphism x↦pm−nxx \mapsto p^{m-n}x of T\mathbf{T} onto itself, for n≤mn \leq m, pp being a given prime number. The topological group Tp=lim⁡←Gn\mathbf{T}_p = \lim_{\leftarrow} G_n is called the pp-adic solenoid; it is a compact connected commutative group.

a) For every nn, the continuous homomorphism fn:Tp→Gnf_n: \mathbf{T}_p \to G_n is surjective and its kernel is isomorphic to the group Zp\mathbf{Z}_p of pp-adic integers (cf. III, p. 85, exerc. 1 a)).

b) Let φ\varphi be the canonical homomorphism R→R/Z=T\mathbf{R} \to \mathbf{R}/\mathbf{Z} = \mathbf{T}. For every x∈Rx \in \mathbf{R}, put θ(x)=(φ(x/pn))n∈N\theta(x) = (\varphi(x/p^n))_{n \in \mathbf{N}}; now prove that θ\theta is a continuous injective homomorphism of R\mathbf{R} into Tp\mathbf{T}_p, and that θ(R)\theta(\mathbf{R}) is a everywhere dense subgroup of Tp\mathbf{T}_p.

c) Let I be an open interval in R\mathbf{R}, of center 0 and of length < 1 ; now prove that in TpT_p, the subspace f0−1(φ(I))f_0^{-1}(\varphi(I)) is homeomorphic to the product I×ZpI \times \mathbf{Z}_p. In particular, the group TpT_p is not locally connected. d) Now prove that every closed subgroup H of TpT_p distinct from TpT_p and from {0}\{0\}, is totally discontinuous and isomorphic to a group of the form Z/nZ\mathbf{Z}/n\mathbf{Z} or (Z/nZ)×Zp(\mathbf{Z}/n\mathbf{Z}) \times \mathbf{Z}_p, where n is an integer prime to pp (use the prop. 3 of III, p. 62). e) Now prove that TpT_p is a compact connected indecomposable space, that is to say that there does not exist a covering of TpT_p formed by two compact connected sets P, Q distinct from TpT_p. (Observe that there exists an integer n such that fn(P)≠Gnf_n(P) \neq G_n and fn(Q)≠Gnf_n(Q) \neq G_n, and examine the sets fn+1(P)f_{n+1}(P) and fn+1(Q)f_{n+1}(Q) to obtain a contradiction.)*

Solution

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Machine translation of the English, by gpt-5-mini. Not checked by a person. That model is a cut down version of the one the rest of this language was written by.