Bourbaki

Exercise 6, § 7

General Topology, III

Bourbaki marks this one as harder than the rest, it is set in small type as supplementary.

Let (Gn,fnm)n∈N(G_n, f_{nm})_{n \in \mathbf{N}} be the inverse system of compact groups such that Gn=T=R/ZG_n = T = \mathbf{R}/\mathbf{Z} for each nn, and fnmf_{nm} is the continuous homomorphism x→pm−nxx \to p^{m-n}x of TT onto itself, for n≤mn \leq m (pp being a given prime number). The topological group Tp=lim←⁡GnT_p = \varprojlim G_n is called the pp-adic solenoid; it is a compact connected commutative topological group.

a) For each nn, the continuous homomorphism fn:Tp→Gnf_n : T_p \to G_n is surjective, and its kernel is isomorphic to the group Zp\mathbf{Z}_p of pp-adic integers [cf. Exercise 1 a)].

b) Let φ\varphi be the canonical homomorphism R→R/Z=T\mathbf{R} \to \mathbf{R}/\mathbf{Z} = \mathbf{T}. For each x∈Rx \in \mathbf{R}, put θ(x)=(φ(x/pn))n∈N\theta(x) = (\varphi(x/p^n))_{n \in \mathbf{N}}; show that θ\theta is an injective continuous homomorphism of R\mathbf{R} into Tp\mathbf{T}_p, and that θ(R)\theta(\mathbf{R}) is a dense subgroup of Tp\mathbf{T}_p.

c) Let II be an open interval in R\mathbf{R}, with centre 00 and length <1< 1. Show that the subspace f0−1(φ(I))f_0^{-1}(\varphi(I)) of Tp\mathbf{T}_p is homeomorphic to the product I×ZpI \times \mathbf{Z}_p. In particular, the group Tp\mathbf{T}_p is not locally connected.

d) Show that every closed subgroup HH of Tp\mathbf{T}_p, other than Tp\mathbf{T}_p or {0}\{0\}, is totally disconnected and isomorphic to a group of the form Z/nZ\mathbf{Z}/n\mathbf{Z} or (Z/nZ)×Zp(\mathbf{Z}/n\mathbf{Z}) \times \mathbf{Z}_p, where nn is an integer prime to pp (use Proposition 3 of no. 3).

e) Show that Tp\mathbf{T}_p is an indecomposable compact connected space, i.e. that Tp\mathbf{T}_p cannot be covered by two compact connected sets P,QP, Q neither of which is equal to Tp\mathbf{T}_p. (Observe that there is an integer nn such that fn(P)≠Gnf_n(P) \neq G_n and fn(Q)≠Gnf_n(Q) \neq G_n, and examine the sets fn+1(P)f_{n+1}(P) and fn+1(Q)f_{n+1}(Q) to get a contradiction). \*

Solution

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Transcribed from the printed volume. Not translated.