Bourbaki

Exercise 10, § 4

General Topology, IX, p. 102

Bourbaki marks this one as harder than the rest.

Prove now that, in a normal space X, every subspace Y which is a countable union of closed sets, is normal. (Let A, B be two closed subsets of Y, with no common point, and suppose that Y is the union of an increasing sequence (Fn)(F_n) of closed subsets of X. Define by induction two sequences (Un),(Vn)(U_n), (V_n) of open subsets of X, such that: 1∘Un‾∩Fn1^\circ \overline{U_n} \cap F_n and Vn‾∩Fn\overline{V_n} \cap F_n are disjoint; 2∘Un∩Fn2^\circ U_n \cap F_n contains A∩FnA \cap F_n and all the sets Ui‾∩Fi‾\overline{U_i} \cap \overline{F_i} for 1≤i≤n1 \leq i \leq n, and Vn∩FnV_n \cap F_n contains B∩FnB \cap F_n and all the sets Vi‾∩Fi‾\overline{V_i} \cap \overline{F_i} for 1≤i<n1 \leq i < n.

Solution

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Machine translation of the English, by gpt-5-mini. Not checked by a person. That model is a cut down version of the one the rest of this language was written by.