Bourbaki

Exercise 25, § 4

General Topology, IX, p. 107

Bourbaki marks this one as harder than the rest.

(a) Let X be a regular space such that, for every open covering R\mathscr{R} of X, there exists a locally finite covering A\mathscr{A} (not necessarily open) of X which is finer than R\mathscr{R}. Then, for every open covering R\mathscr{R} of X, there exists a closed locally finite covering F\mathscr{F} of X which is finer than R\mathscr{R}. (For every x∈Xx \in X, let VxV_x be an open neighbourhood of xx such that V‾x\overline{V}_x is contained in a set of R\mathscr{R}. Consider a locally finite covering B\mathscr{B} finer than the covering formed by the VxV_x, then the covering F\mathscr{F} formed by the closures of the sets of B\mathscr{B}.) (b) Let X be a separated space such that, for every open covering R\mathscr{R} of X, there exists a closed locally finite covering F\mathscr{F}, finer than R\mathscr{R}. Prove that X is paracompact. (Let R\mathscr{R} be an open covering of X, A\mathscr{A} a locally finite covering of X, finer than R\mathscr{R}; for every xx, let WxW_x be an open neighbourhood of xx meeting only a finite number of sets of A\mathscr{A}. Let F\mathscr{F} be a closed locally finite covering finer than the covering formed by the WxW_x. For every A∈AA \in \mathscr{A}, let UAU_A be a set of R\mathscr{R} containing A, and let CAC_A be the union of the sets F∈FF \in \mathscr{F} such that A∩F=∅A \cap F = \varnothing. Prove that when A ranges over A\mathscr{A}, the sets UA∩(X−CA)U_A \cap (X - C_A) form an open locally finite covering finer than R\mathscr{R}.) (c) Deduce from a) and b) that if X is a regular space such that, for every open covering R\mathscr{R} of X, there exists a locally finite covering (not necessarily open) finer than R\mathscr{R}, X is paracompact.

Solution

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Machine translation of the English, by gpt-5-mini. Not checked by a person. That model is a cut down version of the one the rest of this language was written by.