Exercise 25, § 4
General Topology, IX, p. 107
Bourbaki marks this one as harder than the rest.
(a) Let X be a regular space such that, for every open covering of X, there exists a locally finite covering (not necessarily open) of X which is finer than . Then, for every open covering of X, there exists a closed locally finite covering of X which is finer than . (For every , let be an open neighbourhood of such that is contained in a set of . Consider a locally finite covering finer than the covering formed by the , then the covering formed by the closures of the sets of .) (b) Let X be a separated space such that, for every open covering of X, there exists a closed locally finite covering , finer than . Prove that X is paracompact. (Let be an open covering of X, a locally finite covering of X, finer than ; for every , let be an open neighbourhood of meeting only a finite number of sets of . Let be a closed locally finite covering finer than the covering formed by the . For every , let be a set of containing A, and let be the union of the sets such that . Prove that when A ranges over , the sets form an open locally finite covering finer than .) (c) Deduce from a) and b) that if X is a regular space such that, for every open covering of X, there exists a locally finite covering (not necessarily open) finer than , X is paracompact.
Solution
No solution has been written yet.