Bourbaki

Exercise 11, § 4

General Topology, X, p. 57

Bourbaki marks this one as harder than the rest.

(a) Let XX be a completely regular space, YY a closed subspace of XX; the mapping φ:u↦u∣Y\varphi : u \mapsto u|Y of Cb(X;R)C^b(X; \mathbf{R}) into Cb(Y;R)C^b(Y; \mathbf{R}) is a continuous linear mapping of norm ≤1\leq 1. If XX is normal, φ\varphi is a strict surjective morphism; moreover, if XYX_Y denotes the quotient space of XX obtained by identifying all the points of YY (space which is normal by virtue of IX, p. 105, exerc. 19), the kernel of φ\varphi identifies (with its norm) with the subspace of Cb(XY;R)C^b(X_Y; \mathbf{R}) formed by the functions which vanish at the point ω\omega, canonical image of YY in XYX_Y.

(b) Suppose that XX is metrisable and that the boundary of YY in XX is of countable type. Now prove that φ:u↦u∣Y\varphi : u \mapsto u|Y is a strict right invertible morphism (III, p. 47, prop. 3). (Let dd be a distance compatible with the topology of XX; let (an)(a_n) be a sequence of points of Fr(Y)Fr(Y), dense in Fr(Y)Fr(Y), and let Vn,mV_{n,m} be the set of the x∈Xx \in X such that d(x,an)<1/md(x, a_n) < 1/m and d(x,Y)>1/2md(x, Y) > 1/2m; form a family of continuous mappings fn,mf_{n,m} of XX into (0,1)(0, 1), such that the support of fn,mf_{n,m} is contained in Vn,mV_{n,m} and that one has ∑n,mfn,m(x)=1\sum_{n,m} f_{n,m}(x) = 1 in CY\mathscr{C} Y, the family (fn,m)(f_{n,m}) being uniformly summable in a suitable neighbourhood of every point of CY\mathscr{C} Y. Show then that for every function v∈Cb(Y;R)v \in C^b(Y; \mathbf{R}), the function uu equal to vv in YY, to ∑m,nv(an)fn,m(x)\sum_{m,n} v(a_n) f_{n,m}(x) for every x∈CYx \in \mathscr{C} Y, belongs to Cb(X;R)C^b(X; \mathbf{R}) and is such that φ(u)=v\varphi(u) = v.\footnote{This result does not extend to the case where XX is the non-metrisable compact space βN\beta N, YY the closed set βN−N\beta N - N (EVT, IV, § 5, exerc. 5 c))}

Solution

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Machine translation of the English, by gpt-5-6-mini. Not checked by a person. That model is a cut down version of the one the rest of this language was written by.