Exercise 19, § 4
General Topology, X, p. 60
(a) Let be a completely regular space; now prove that a point of cannot admit a fundamental system of connected neighbourhoods in . Observe that there exists a function which tends to at the point . For , let be the set of the such that for an . If, for example, is adherent to , observe that and are normally separated in (IX, p. 87, exerc. 15), and consequently that there exists an open neighbourhood of in such that . Now prove that it is not possible that there exists a connected neighbourhood of , by using IX, p. 87, exerc. 16.
(b) Deduce from a) that, in order that be locally connected, it is necessary and sufficient that be locally connected and weierstrassian (cf. IX, p. 105, exerc. 21).
Solution
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