Bourbaki

Exercise 16, § 7

Tag 02H3, permanent. Cite it as [Bourbaki, Tag 02H3].

Spectral Theories, I, p. 190

Let XX be a locally compact space, μ\mu a positive measure of total mass 1 on XX and f:X→Xf: X\rightarrow X a mapping such that f(μ)=μf(\mu) =\mu.

(a) The mapping φ↦φ∘f\varphi \mapsto \varphi \circ f induces a unitary endomorphism ufu_f of L2(X,μ)L^2(X, \mu).

(b) The real number 1 is an eigenvalue of ufu_f of multiplicity 1 if and only if, for every measurable subset A of X such that f−1(A)=Af^{-1}(A) = A, one has μ(A)∈{0,1}\mu(A)\in \{0,1\}. One then says that ff is μ\mu-ergodic.

(c) Let E⊂L2(X,μ)E\subset L^2(X, \mu) be the proper subspace of ufu_f for the eigenvalue 1. The sequence (vN)N∈N(v_N)_{N\in\mathbf{N}} defined by

vN=1N∑n=0N−1ufn v_N=\frac{1}{N}\sum_{n=0}^{N-1}u_f^n

converges to the orthogonal projection onto E in the space L(L2(X,μ))\mathscr{L}(L^2(X, \mu)) endowed with the topology of simple convergence (“von-Neumann ergodic theorem”).(Note that the orthogonal of E is the closure of the image of uf−1Eu_f-1_E; verify then that vN(φ)→0v_N(\varphi )\rightarrow 0 when φ∈E∘.\varphi \in E^{\circ}.)

(d) One defines an endomorphism u~f\widetilde{u}_f of L1(X,μ)L^1(X, \mu) as in question a), and one sets

v~N=1N∑n=0N−1u~fn. \widetilde{v}_N=\frac{1}{N}\sum_{n=0}^{N-1}\widetilde{u}_f^n.

For every φ∈L1(X,μ)\varphi \in L^1(X, \mu), the sequence (v~N(f))N∈N(\widetilde{v}_N(f))_{N\in\mathbf{N}} converges in L1(X,μ)L^1(X, \mu) towards an element φ~\widetilde{\varphi} of the proper subspace of u~f\widetilde{u}_f for the eigenvalue 1. (First consider the case where φ\varphi is bounded, and apply the preceding question.)

(e) Let I be a finite set and X=IZX = I^{\mathbf{Z}} endowed with the product measure of the measures μn\mu_n on I such that μn(i)=1/\mu_n(i) = 1/Card(I) for every i∈Ii\in I. Put f((in))=(in+1)f((i_n)) = (i_{n+1}) for every (in)∈X(i_n)\in X. Then f(μ)=μf(\mu) =\mu and ff is μ\mu-ergodic (“Bernoulli shift”).

(f) Let X=R/ZX =\mathbf{R}/\mathbf{Z} and μ\mu the normalised Haar measure on X. Let a∈Xa\in X and put f(x)=x+af(x) =x+a. Then f(μ)=μf(\mu) =\mu and ff is μ\mu-ergodic if and only if aa is the class of an irrational number.

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Machine translation of the English, by gpt-5-6-mini. Not checked by a person. That model is a cut down version of the one the rest of this language was written by.