Bourbaki

Exercise 37, § 1

Tag 02LD, permanent. Cite it as [Bourbaki, Tag 02LD].

Spectral Theories, II, p. 278

On keeps the notations of the preceding exercise. (a) Let f:C→Cf:\mathbf{C}\rightarrow \mathbf{C} be an element of E1/2\mathscr{E}_{1/2} such that the restriction of ff to R\mathbf{R} belongs to L2(R)L^2(\mathbf{R}). For every z∈C−Zz\in \mathbf{C}-\mathbf{Z}, we have

f(z)=f(z) = sin(ππz\pi \pi z)∑n∈Z(−1)nf(n)z−n\sum_{n\in\mathbf{Z}}(-1)^n\frac{f(n)}{z-n}.

(Use the Paley-Wiener theorem and formula a) of Exercise 1.)

(b) Let f:C→Cf:\mathbf{C}\rightarrow \mathbf{C} be an element of E1/2\mathscr{E}_{1/2} such that ff is bounded on R\mathbf{R}. For every z∈C−Zz\in \mathbf{C}-\mathbf{Z}, we have

f(z)=f(0)+f(z) =f(0) + sin(ππz\pi \pi z)(f′(0)+∑n∈Z−{0}(−1)nzf(n)−f(0)n(z−n))(f'(0) +\sum_{n\in\mathbf{Z}-\{0\}}(-1)^nz\frac{f(n) -f(0)}{n(z-n)})

(apply the preceding question to the function defined by z↦(f(z)−f(0))/zz\mapsto (f(z)-f(0))/z for z≠0z\not= 0 and which maps 0 to f′(0)f'(0)).

(c) Let ff be an element of E1/2\mathscr{E}_{1/2} bounded on R\mathbf{R}. Then f′f' is bounded on R\mathbf{R} and we have

supx∈R∣f′(x)∣⩽2_{x\in\mathbf{R}}|f'(x)|\leqslant 2 supx∈R∣f(x)∣_{x\in\mathbf{R}}|f(x)|

(“Bernstein inequality”; reduce to majorizing ∣f′(1/2)∣|f'(1/2)| and apply the preceding formula).

(d) Let ff be an element of E1/2\mathscr{E}_{1/2} such that the restriction of ff to R\mathbf{R} belongs to L2(R)L^2(\mathbf{R}). Let uu and vv be the 1-periodic functions on R\mathbf{R} defined by

u(t)=f^(t)+f^(t−1),v(t)=2iπ(tf^(t)+(t−1)f^(t−1)) u(t) =\widehat{f}(t) +\widehat{f}(t-1),v(t) = 2i\pi (t\widehat{f}(t) + (t-1)\widehat{f}(t-1))

for 0⩽t<10\leqslant t <1. For almost every t∈[−1,1]t\in [-1,1], we have

f^(t)=(1−∣t∣)u(t)+(2iπ)−1\widehat{f}(t) = (1- |t|)u(t) + (2i\pi )^{-1} s(tt)v(t)v(t),

and the coefficients of the Fourier series of uu and vv are f(−n)f(-n) and f′(−n)f'(-n), respectively, for n∈Zn\in \mathbf{Z}.

(e) Let f∈E1/2f\in \mathscr{E}_{1/2} as in the preceding question. We have for every z∈Cz\in \mathbf{C} the formula

f(z)=(f(z) =( sin(ππz\pi \pi z))2{(∑n∈Zf(n)(z−n)2+∑n∈Zf′(n)z−n}^2\{(\sum_{n\in\mathbf{Z}}\frac{f(n)}{(z-n)^2}+\sum_{n\in\mathbf{Z}}\frac{f'(n)}{z-n}\},

where the series converges symmetrically in O(C)\mathscr{O}(\mathbf{C}), that is to say, uniformly on the compact subsets of C\mathbf{C}. (Use the formulas of question f) of Exercise 1.)

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