Bourbaki

Exercise 4, § 2

Tag 02RD, permanent. Cite it as [Bourbaki, Tag 02RD].

Spectral Theories, III, p. 120

Let α∈]0,1]\alpha \in ]0,1]. Let I be a compact interval of R\mathbf{R}. We denote by Cα(I)\mathscr{C}^{\alpha}(I) the vector subspace of C(I)\mathscr{C}(I) formed by the functions ff such that there exists C⩾0C\geqslant 0 satisfying

∣f(x)−f(y)∣⩽C∣x−y∣α |f(x)-f(y)|\leqslant C|x-y|^{\alpha}

for all (x,y)∈I×I(x, y)\in I\times I.

We equip Cα(I)\mathscr{C}^{\alpha}(I) with the norm

∥f∥α=\|f\|_{\alpha}= supx∈I∣f(x)∣+_{x\in I}|f(x)|+ sup(x,y)∈I×I∣f(x)−f(y)∣∣x−y∣α_{(x,y)\in I\times I}\frac{|f(x) -f(y)|}{|x-y|^{\alpha}}.

x≠yx\not =y

(a) The space Cα(I)\mathscr{C}^{\alpha}(I) is a Banach space.

(b) The canonical injection Cα(I)→C(I)\mathscr{C}^{\alpha}(I)\rightarrow \mathscr{C}(I) is compact.

(c) If 0<α<β⩽10< \alpha < \beta \leqslant 1, then the canonical injection Cβ(I)→Cα(I)\mathscr{C}^{\beta}(I)\rightarrow \mathscr{C}^{\alpha}(I) is compact.

(d) The Sobolev space H1(I˚)(H^1(\mathring{I}) (cf. IV, p. 221, no14^o14) identifies with a subspace of C1/2\mathscr{C}^{1/2}(I), but the canonical injection H1(I˚)→C1/2(I)H^1(\mathring{I})\rightarrow \mathscr{C}^{1/2}(I) is not compact.

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Machine translation of the English, by gpt-5-6-mini. Not checked by a person. That model is a cut down version of the one the rest of this language was written by.