Bourbaki

Exercise 22, § 4

Tag 0356, permanent. Cite it as [Bourbaki, Tag 0356].

Spectral Theories, IV, p. 351

We resume the notation of the preceding exercise.

a) There exist functions f1f_1 and f2f_2 in C2([a,b])\mathscr{C}^2([a, b]) such that −fi′′+qfi=0-f''_i+qf_i= 0 and

f1(0)=0,f1′(0)=1 f_1(0) = 0,f'_1(0) = 1
f2(1)=0,f2′(1)=−1 f_2(1) = 0,f'_2(1) =-1

These functions are the unique solutions of these equations and the function w=w= f1f2′−f1′f2f_1f'_2-f'_1f_2 is constant.

b) Let g∈C([0,1])g\in \mathscr{C}([0,1]). There exists a unique function φ∈C2([0,1])\varphi \in \mathscr{C}^2([0,1]) such that

−φ′′+qφ=g -\varphi ''+q\varphi =g

and one has φ=c1f1+c2f2\varphi =c_1f_1+c_2f_2, where

c1(x)=−1w∫x1g(y)f2(y)dμ(y),c2(x)=−1w∫0xg(y)f1(y)dμ(y) c_1(x) =-\frac{1}{w}\int_x^1g(y)f_2(y)d\mu(y),c_2(x) =-\frac{1}{w}\int_0^xg(y)f_1(y)d\mu(y)

for every x∈[0,1]x\in [0,1]. c) The partial operator SLq_q is surjective; its inverse is the mapping g↦φg\mapsto \varphi and there exists a function G∈C([0,1]2)G\in \mathscr{C}([0,1]^2) such that

SLq−1(g)(x)=∫01G(x,y)g(y)dμ(y)^{-1}_q(g)(x) =\int_0^1G(x, y)g(y)d\mu(y)

for every g∈C([0,1])g\in \mathscr{C}([0,1]) and almost every x∈[0,1]x\in [0,1]. One has G(x,y)=G(y,x)G(x, y) = G(y, x) for every (x,y)∈[0,1]2(x, y)\in [0,1]^2.

d) The operator SLq−1^{-1}_q is compact and injective on L2([0,1],μ)L^2([0,1], \mu).

e) The functions (φn)(\varphi_n) form an orthonormal basis of L2([0,1])L^2([0,1]), and the spectrum of SLq_q coincides with the set of its eigenvalues.

Solution

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Machine translation of the English, by gpt-5.4. Not checked by a person.