Bourbaki

Exercise 4, § 4

Tag 03F8, permanent. Cite it as [Bourbaki, Tag 03F8].

Spectral Theories, V, p. 505

Bourbaki marks this one as harder than the rest.

Let G be a group and let A and B be subgroups of G. Let φ:A→B\varphi : A\rightarrow B be an isomorphism.

Let r′\boldsymbol{r}' be a family in the free group F(G) such that G is isomorphic to the group F(G,r′)F(G,\boldsymbol{r}') (A, I, p. 87, No. 6). The HNN extension of G according to φ\varphi is by definition the group Gφ=F(X,r)G^{\varphi}= F(X,\boldsymbol{r}) where X is the sum of the sets G, A, B and of an element tt, and where r\boldsymbol{r} is the sum family of r′\boldsymbol{r}' and of the relators t−1at=φ(a)t^{-1}at=\varphi (a) for all a∈Aa\in A.

We denote by j:G→Gφj: G\rightarrow G^{\varphi} the unique homomorphism such that j(g)j(g) is the element represented by gg in GφG^{\varphi}.

a) Let k⩾1k\geqslant 1 be an integer and let (g0,ε1,g1,...,εk,gk)(g_0, \varepsilon_1, g_1, . . . , \varepsilon_k, g_k) be a finite family such that gi∈Gg_i\in G and εi∈{−1,1}\varepsilon_i\in \{-1,1\} for all ii. Suppose that there exists no integer jj such that 1⩽j⩽k−11\leqslant j\leqslant k-1 and

(εj,εj+1)=(−1,1),gi∈A (\varepsilon_j, \varepsilon_{j+1}) = (-1,1),g_i\in A

or else

(εj,εj+1)=(1,−1),gi∈B (\varepsilon_j, \varepsilon_{j+1}) = (1,-1),g_i\in B

Then the element

j(g0)tε1j(g1)⋯tεkj(gk) j(g_0)t^{\varepsilon_1}j(g_1)\cdots t^{\varepsilon_k}j(g_k)

of GφG^{\varphi} is not the identity element ("Britton's Lemma".)

b) The homomorphism jj is injective.

c) Let aa and bb be distinct sets. Let G be the group F({a,b},a−1b2ab−3)F(\{a, b\}, a^{-1}b^2ab^{-3}). Put b1=a−1bab_1=a^{-1}ba. Let H be a normal subgroup of finite index of G and π:G→G/H\pi : G\rightarrow G/H the canonical projection. One has [b1,b]∈[b_1, b]\in Ker(π\pi ).

d) The group G admits no faithful finite-dimensional representation. (Prove that G is not residually finite.)

Solution

No solution has been written yet.

Cited by

Nothing.

Cites

Nothing.

Machine translation of the English, by gpt-5.4. Not checked by a person.